www.qprq.net > jAvA "[A,B,C]" 类型字符串如何转成 list 即[A,B,C...

jAvA "[A,B,C]" 类型字符串如何转成 list 即[A,B,C...

这样的我们只有自己写代码分割,首先我们提取[]里面的内容,然后使用,分割成数组,然后转在list 代码如下: String demo = "[a,b,c]"; String demosub = demo.substring(1,demo.length()-1); String demoArray[] = demosub.split(","); List de...

这个简单,首先你说有,分隔,那就去掉“,”。方法是split String str="a,b,c";String arr[]=str.split(","); //使用split可以转换为数组arr[0]=a;String newStr="";for (int i =arr.length-1; i >arr.length; i--) {newStr+=arr[i]; //使用for循...

public static void main(String[] args) { List list = new ArrayList(); list.add("a"); list.add("b"); list.add("c"); list.add("d"); list.add("e"); list.add("f"); int delIndex = 0; for (int i = 0; i < list.size(); i++) {String tem...

String str = "abcdefghijklmnopqrstuvwxyz"; char[] strS = new char[str.length()]; for (int i = 0; i < str.length(); i++) { strS[i] = str.charAt(i); } //思路:将字符串数组变为字符数组 ^-^

代码: public class Test {public static final void main(String[] args) {String s = "ab c,d";char[] chs = s.toCharArray();// 字母对应的ASCII码值 65~90 97~122List list = new ArrayList();for (char ch : chs) {if ((64 < ch && ch < ...

public static void main(String[] args) { String s = "a,b,c"; String [] arr = s.split(","); for (int i = 0; i < arr.length; i++) { System.out.print(" "+arr[i]); } } 这是针对普遍的字符串,如果是特定的字节还可以用 public static vo...

public class split { public static void main(String[] args) { String str = ",a,b,c,e,f,,,"; //数据 String[] str1 = str.split(","); for(String str2: str1){ System.out.println(str2); } } }

1. 初始化3个数组2. 用System.arraycopy函数对其进行分析3. 代码如下:public class Yugi { public static void main(String[] args){ String[] array = {"a","b","c","d","c","d","e"}; String[] other = new String[0]; String[] orig = new S...

public class Test22 { public static void main(String[] args) { String s = "abcd"; char[] chars = s.toCharArray(); String[] ss = new String[chars.length]; for (int i = 0; i < chars.length; i++) { ss[i] = String.valueOf(chars[i])...

这种题目超过10行代码就等于没写。 public static void main(String[] args) { String str = "ABCDEFGHJ"; char start='A'; char end ='Z'; for(int i = 0 ; i < (int)(end-start+1) ;i++){ str = str.replaceAll(String.valueOf((char)(start+(...

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